Hello
I was hoping someone could help me with the following integral problem. Solve the following:-
Find the integral of = > x^2 * Cos(x).dx
I know that i must use integration but do i need to apply integration by parts twice i.e
x^2 * Cos(x) = x^2 * Sin(x) - S 2x * sin(x) (S is the integral sign)
Do i need to use integration by parts for S 2x * sin(x)?
Can anyone help?
Thank you.
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Verified answer
∫ x^2cos(x)dx
use integraion by parts..
let u=x^2....dv=cos(x)
du=2xdx v=sin(x)
∫ uvdv=uv-∫vdu
=x^2sin(x) - 2∫ xsin(x)dx
let u=x dv=sin(x)
du=dx v=-cos(x)
=x^2sin(x)-2[-xcos(x) - ∫ -cos(x)dx]
=x^2sin(x)-2[-xcos(x) +sin(x)]+C
=x^2sin(x)+2xcos(x)-2sin(x)+C
=x^2sin(x)-2sin(x)+2xcos(x)+C
=sin(x)(x^2-1)+2xcos(x)+C answer//
You are right of course. There's actually a neat trick to questions which require multiple integration by parts. Start as usual. Then go on inegrating one function and differentiating the other one applying alternatively plus and minus starting with plus.
Example S x^3.cos x dx
Now go on diff x^3 and inegrating cos x
=x^3(sin x)-(3x^2)(-cos x)+(6x)(-sin x)-(6)(cos x)
Cheers!
Yes, you do.
∫ x^2 cos x dx
Let u = x^2 and dv = cos x dx
then du = 2x dx and v = sin x
x^2 sin x - 2 ∫ x sin x dx
Let U = x and dV = sin x dx
then dU = dx and V = - cos x
x^2 sin x - 2x(- cos x) - 2 ∫ (- cos x dx) = x^2 sin x + 2x cos x + 2 sin x + C
Yes, you need to use integration by parts twice.
∫ x² cos(x) dx
u = x² . . . . . . . dv = cos(x) dx
du = 2x dx . . . v = sin(x)
∫ u dv = u*v - ∫ v du
∫ x² cos(x) dx = x² sin(x) - ∫ 2x sin(x) dx
∫ x² cos(x) dx = x² sin(x) - 2 ∫ x sin(x) dx
Integrate by parts again:
u = x . . . . . dv = sin(x) dx
du = dx . . . v = -cos(x)
∫ x² cos(x) dx = x² sin(x) - 2 (-x cos(x) - ∫ - cos(x) dx)
∫ x² cos(x) dx = x² sin(x) + 2x cos(x) - 2 ∫ cos(x) dx
∫ x² cos(x) dx = x² sin(x) + 2x cos(x) - 2 sin(x) + C
∫x²*cos(x) dx
Use integration by parts.
u = x²
dv = cos(x) dx
v = sin(x)
du = 2x dx
uv - ∫v du
x²*sin(x) -2*∫x*sin(x) dx
Use integration by parts again:
u = x
dv=sin(x) dx
v = -cos(x)
du = dx
∫x²*cos(x) dx = x²*sin(x) + 2x*cos(x) - 2*sin(x) + C
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Your approach is correct..You can test your answer by differentiating it to get back x^2.cosx
IVAN
yes you have use to use intergation by parts again to xsin(x)